Geodesic for a linear connection: Difference between revisions

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Equivalently, we say that <math>\gamma</math> is a geodesic if:
Equivalently, we say that <math>\gamma</math> is a geodesic if:


<math>\frac{D}{dt}(\gamma'(t)} = 0 \forall t</math>
<math>\frac{D}{dt}(\gamma'(t)) = 0 \forall t</math>


(with the derivative interpreted as a suitable one-sided derivative at the endpoints).
(with the derivative interpreted as a suitable one-sided derivative at the endpoints).

Latest revision as of 21:17, 6 January 2012

Definition

Given data

Definition part

Consider a smooth curve γ:[0,1]M. Let D/dt denote the connection along γ induced by , and consider the transport along γ for the connection D/dt. Then, we say that γ is a geodesic for if, under that transport, the tangent vector γ(0) at γ(0) gets transported, at time t, to the tangent vector γ(t) at γ(t).

Equivalently, we say that γ is a geodesic if:

Ddt(γ(t))=0t

(with the derivative interpreted as a suitable one-sided derivative at the endpoints).