Sard's theorem: Difference between revisions

From Diffgeom
No edit summary
 
No edit summary
Line 2: Line 2:


Suppose <math>M</math> and <math>N</math> are [[differential manifold]]s and <math>f:M \to N</math> is a [[smooth map]] between them. Then, the set of [[regular value]]s of <math>f</math> is a [[measure zero subset of a differential manifold|subset of measure zero]] in <math>N</math>.
Suppose <math>M</math> and <math>N</math> are [[differential manifold]]s and <math>f:M \to N</math> is a [[smooth map]] between them. Then, the set of [[regular value]]s of <math>f</math> is a [[measure zero subset of a differential manifold|subset of measure zero]] in <math>N</math>.
==Applications==
Suppose <math>M</math> and <math>N</math> are differential manifolds, and the dimension of <math>M</math> is strictly less than the dimension of <math>N</math>. Then, if <math>f:M \to N</math> is a [[smooth map]], the image <math>f(M)</math> has measure zero as a subset of <math>N</math>. In particular, <math>f</math> cannot be surjective.

Revision as of 00:40, 13 January 2008

Statement

Suppose M and N are differential manifolds and f:MN is a smooth map between them. Then, the set of regular values of f is a subset of measure zero in N.

Applications

Suppose M and N are differential manifolds, and the dimension of M is strictly less than the dimension of N. Then, if f:MN is a smooth map, the image f(M) has measure zero as a subset of N. In particular, f cannot be surjective.